Re: Celcius to Farenheight and vice versa

From: Paul Burkhardt (burkhard@aries.scs.uiuc.edu)
Date: Tue Apr 21 1998 - 08:56:08 PDT

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Date: Tue, 21 Apr 1998 10:56:08 -0500 (CDT)
From: Paul Burkhardt <burkhard@aries.scs.uiuc.edu>
To: cp@opus.hpl.hp.com
Message-Id: <aabcdefg1331$foo@default>
Subject: Re: Celcius to Farenheight and vice versa

> the constant must be 32 to correspond with the freezing point in F. This
> constant holds for all other values of C. You can then manipulate the
> formula to get the C from F conversion.
>
> F = 9/5C + 32 or C = 5/9F - 32
>
> Paul Burkhardt

Oops! How many of you caught my mistake? :)

C = 5/9(F - 32) <---- need parentheses

Paul Burkhardt

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